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The Student Solutions Manual to accompany The Systematic Identification of Organic Compounds, 9th Edition is an essential resource for any student using the parent text in class. Providing complete solutions to all practice problems provided in the textbook, this book allows you to assess your understanding of difficult material and clarify complex topics. Fully aligned with the text, this book details structures, formulas, mechanisms, and more to help you pinpoint areas of difficulty and focus your study time for more efficient learning.
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Veröffentlichungsjahr: 2023
Cover
Title Page
Copyright Page
Preface Page
Chapter 4: Preliminary Examination, Physical Properties, and Elemental Analysis
Chapter 5: Classification of Organic Compounds by Solubility
Chapter 6: Separation of Mixtures
Chapter 7: Nuclear Magnetic Resonance Spectrometry
Chapter 8: Infrared Spectrometry
Chapter 9: Mass Spectrometry
Chapter 10: Chemical Tests for Functional Groups
Chapter 11: The Preparation of Derivatives
Chapter 13: Structural Problems
PROBLEM SET 1
PROBLEM SET 2
PROBLEM SET 3
PROBLEM SET 4
PROBLEM SET 5
PROBLEM SET 6
PROBLEM SET 7
PROBLEM SET 8
PROBLEM SET 9
PROBLEM SET 10
PROBLEM SET 11
PROBLEM SET 12
PROBLEM SET 13
PROBLEM SET 14
PROBLEM SET 15
PROBLEM SET 16
PROBLEM SET 17
PROBLEM SET 18
PROBLEM SET 19
PROBLEM SET 20
End User License Agreement
Cover Page
Title Page
Copyright Page
Preface
Table of Contents
Begin Reading
Wiley End User License Agreement
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Ninth Edition
CHRISTINE K. F. HERMANN
TERENCE C. MORRILL
RALPH L. SHRINER
REYNOLD C. FUSON
Copyright © 2023 by John Wiley & Sons, Inc. All rights reserved.
Published by John Wiley & Sons, Inc., Hoboken, New Jersey.Published simultaneously in Canada.
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Library of Congress Cataloging‐in‐Publication Data applied for:
Paperback: 9781119799856
Cover design by Wiley
For the first six editions of this textbook, no solutions manual was available. As some of the problems presented throughout the textbook are quite difficult, I wrote the solutions manual as an aid to users of the textbook. The textbook contains no problems in Chapters 1, 2, 3, and 12.
I would like to thank Terence Morrill for the answers to Problem Sets 6–20 in Chapter 13, which is available on a companion website. These answers had been in handwritten form for many years. I would like to thank Danielle Davis for her assistance in writing the solutions manual for the seventh edition. I would like to thank Stephen Pond for his patience and support during the preparation of this edition.
Christine K. F. Hermann
Radford University
N – alcohols, aldehydes, ketones, esters with one functional group and more than five but fewer than nine carbons, ethers, epoxides, alkenes, alkynes, some aromatic compounds (especially those with activating groups).
S
1
– monofunctional alcohols, aldehydes, ketones, esters, nitriles, and amides with five carbons or fewer.
A
2
– weak organic acids; phenols, enols, oximes, imides, sulfonamides, thiophenols, all with more than five carbons; β‐diketones; nitro compounds with α‐hydrogens.
Insoluble in water, soluble in 5% sodium hydroxide solution, soluble in 5% sodium bicarbonate solution.
Soluble in water and ether, litmus paper turned blue.
Insoluble in water, 5% sodium hydroxide solution, and 5% hydrochloric acid solution, but soluble in 96% sulfuric acid solution.
Soluble in water and ether; litmus paper is unchanged in color.
Soluble in water and ether; litmus paper is unchanged in color.
Insoluble in water and 5% sodium bicarbonate solution, but soluble in 5% sodium hydroxide solution.
A
1
S
B
N
S
1
S
1
A
2
Both acyl halides and anhydrides react with water, so any results would be of the carboxylic acid that is formed from the hydrolysis of these compounds.
1‐Propanol is more soluble in water than diethyl ether. 1‐Propanol can hydrogen bond with water, whereas diethyl ether does not hydrogen bond with water.
Pentanedioic acid is more soluble in water than butanedioic acid. Odd carbon number of dioic acids have less intracrystalline forces than even carbon number of dioic acids.
Methyl methacrylate is more soluble in water than poly(methyl methacrylate). Polymers are insoluble in water.
Butanoic acid is more soluble in water than 2‐Bromobutanoic acid. The addition of halogens increases the molecular weight and decreases the solubility.
2‐Methylpropanoic acid is more soluble in water than butanoic acid. Branching lowers the boiling point and lowers intermolecular forces. Thus, a branched compound is more soluble in water than a straight chain molecule.
1‐Chlorobutane is insoluble in water since it is an haloalkane. It is insoluble in 5% sodium hydroxide solution, 5% hydrochloric acid solution, and 96% sulfuric acid solution. Thus 1‐Chlorobutane is in solubility class I.
4‐Methylaniline is insoluble in water since it is an aniline. It is basic, due to the presence of the amino group, and therefore is insoluble in 5% sodium hydroxide solution, but soluble in 5% hydrochloric acid solution, and thus 4‐methylaniline is in solubility class B.
1‐Nitroethane is insoluble in water since it is a weak organic acid. It is soluble in 5% sodium hydroxide solution, but insoluble in 5% sodium bicarbonate solution, and thus 1‐nitroethane is in solubility class A
2
.
Alanine is an amino acid, thus is amphoteric, and soluble in water. Alanine is insoluble in ether and thus in solubility class S
2
.
Benzophenone is insoluble in water because it has more than five carbon atoms. Since it is a neutral compound, containing only carbon, hydrogen, and oxygen, it is insoluble in water, 5% sodium hydroxide solution, and 5% hydrochloric acid solution. It is soluble in 96% sulfuric acid solution. Therefore, benzophenone is in solubility class N.
As a strong organic acid, benzoic acid is insoluble in water, soluble in 5% sodium hydroxide solution, and soluble in 5% sodium bicarbonate solution. Therefore, benzoic acid is in solubility class A
1
.
As a saturated hydrocarbon, hexane is insoluble in water, 5% sodium hydroxide solution, 5% hydrochloric acid solution, and 95% sulfuric acid. Hexane is in solubility class I.
4‐Methylbenzyl alcohol is insoluble in water since it has more than five carbon atoms. It is a neutral compound with only carbon, hydrogen, and oxygen. It is insoluble in water, 5% sodium hydroxide solution and 5% hydrochloric acid solution. However, 4‐methylbenzyl alcohol is soluble in 96% sulfuric acid and thus in solubility class N.
As an amine with less than six carbons, ethylmethylamine is soluble in water. It is soluble in ether and its aqueous solutions turn litmus paper blue, therefore it is basic. Ethylmethylamine is in solubility class S
B
.
Propoxybenzene is insoluble in water because it has more than five carbon atoms. It is a neutral compound with only carbon, hydrogen, and oxygen and is insoluble in 5% sodium hydroxide solution, and 5% hydrochloric acid solution. However, propoxybenzene is soluble in 96% sulfuric acid solution and in solubility class N.
Propanal is soluble in water because it has less than five carbons. As a neutral compound, it is soluble in ether and its aqueous solutions do not change the color of litmus paper. Propanal is in solubility class S
1
.
As an aryl halide, 1,3‐Dibromobenzene is insoluble in water, 5% sodium hydroxide solution, 5% hydrochloric acid solution, and 96% sulfuric acid. 1,3‐Dibromobenzene is in solubility class I.
Propanoic acid is soluble in water because it contains less than five carbon atoms. It is soluble in ether, but its aqueous solutions turn litmus paper red. Propanoic acid is in solubility class S
A
.
As a weak organic acid, benzenesulfonamide is insoluble in water. It is soluble in 5% sodium hydroxide solution but insoluble in 5% sodium bicarbonate solution. Benzenesulfonamide is in solubility class A
2
.
1‐Butanol is soluble in water because it contains less than five carbon atoms. It is soluble in ether and its aqueous solutions do not change the color of litmus. 1‐Butanol is in solubility class S
1
.
Methyl propanoate is soluble in water since it contains less than five carbon atoms. It is soluble in ether and its aqueous solutions do not change the color of litmus. Methyl propanoate is in solubility class S
1
.
4‐Methylcyclohexanone is insoluble in water since it contains more than five carbon atoms. It is also insoluble in 5% sodium hydroxide solution and 5% hydrochloric acid solution, but soluble in 96% sulfuric acid. Therefore, 4‐methylcyclohexanone is in solubility class N.
Since 4‐Aminobiphenyl is an aniline, it is insoluble in water. It is insoluble in 5% sodium hydroxide solution, but soluble in 5% hydrochloric acid solution. 4‐Aminobiphenyl is in solubility class B.
Since 4‐Methylacetophenone contains more than five carbon atoms, it is insoluble in water. It is also insoluble in 5% sodium hydroxide solution and 5% hydrochloric acid solution, but soluble in 96% sulfuric acid. Therefore, 4‐methylacetophenone is in solubility class N.
Naphthalene is insoluble in water since it contains more than five carbon atoms. It is insoluble in 5% sodium hydroxide solution and 5% hydrochloric acid solution. However, naphthalene is soluble in 96% sulfuric acid, and therefore in solubility class N.
Phenylalanine is an amino acid, thus is amphoteric, and soluble in water. Phenylalanine is insoluble in ether and thus in solubility class S
2
.
Benzoin is insoluble in water since it has more than five carbon atoms. It is insoluble in water, 5% sodium hydroxide solution, and 5% hydrochloric acid solution. However, benzoin is soluble in 96% sulfuric acid, and therefore in solubility class N.
As a strong organic acid, 4‐hydroxybenzenesulfonic acid is insoluble in water. However, it is soluble in 5% sodium hydroxide solution and 5% sodium bicarbonate solution. 4‐Hydroxybenzenesulfonic acid is in solubility class A
1
.
Listed in order from least basic to most basic (see next question).
Benzanilide
Solubility class
N
Pentylamine
Solubility class
S
B
Diphenylamine
Solubility class
N
Benzylamine
Solubility class
S
B
4‐Methylaniline
Solubility class
B
Butanamide
Solubility class
S
1
Listed in order from least soluble to most soluble in water.
Smaller alcohols are more soluble.
More hydroxyl groups increase solubility.
Branching increases solubility.
N < S
1
–N < S
B
< S
2
Methanol
Solubility class
S
1
Isopropyl alcohol
Solubility class
S
1
Ethanol
Solubility class
S
1
1‐Butanol
Solubility class
S
1
Butane
Solubility class
I
1,4‐Butanediol
Solubility class
S
2
1‐Butanol
Solubility class
S
1
1‐Butanol
Solubility class
S
1
2‐Methyl‐2‐propanol
Solubility class
S
1
2‐Butanol
Solubility class
S
1
Ammonium butanoate
Solubility class
S
2
3‐Pentanone
Solubility class
S
1
–N
Benzaldehyde
Solubility class
N
Trimethylamine
Solubility class
S
B
The following compounds are listed in order of decreasing activity.
Pentane – volatile
D
‐glucose – low volatility, with certain exceptions these compounds cannot be distilled at atmospheric pressure
Diethylamine – readily distill, many compounds boil below 100 °C
2‐Butanone – readily distill, many compounds boil below 100 °C
Pentane – volatile with steam
D
‐Glucose – not volatile with steam
Diethylamine – volatile with steam
2‐Butanone – volatile with steam
Since glucose is also insoluble in ether, it would be filtered out as Residue 1.
To solve this problem, the number of moles of each substance must be determined.
Compound
grams
MW
moles
2‐Methyl‐2‐propanol
2.47
74.63
0.033
Benzyl alcohol
3.60
108.81
0.033
Benzaldehyde
3.53
106.79
0.033
Acetyl chloride
5.20
78.69
0.066
Acetophenone
4.00
120.92
0.033
N,N
‐Dimethylaniline
28.2
121.95
0.231
The acetyl chloride will react with the 2‐methyl‐2‐propanol and the benzyl alcohol to form the 1,1‐dimethylethyl acetate and the benzyl acetate, respectively.
The hydrogen chloride, produced from the above reactions, reacts with N,N‐dimethylaniline to form N,N‐dimethylanilinium chloride.
If complete reactions are assumed, then the following compounds would be present at the end of a week.
Compound
moles
1,1‐Dimethylethyl acetate
0.033
Benzyl acetate
0.033
Benzaldehyde
0.033
Acetophenone
0.033
N,N
‐Dimethylanilinium chloride
0.066
N,N
‐Dimethylaniline
0.165
Pentane – very nonpolar
Butanoic acid – polar
2‐Butanone – nonpolar
D
‐Fructose – very polar
Pentane < 2‐Butanone < butanonic acid <
D
‐fructose
Since these compounds are alcohols, gas chromatography could be utilized. These compounds would be separated by bp.
Extraction methods would be the preferred method of separating these compounds.
Gas chromatography could be utilized to separate these compounds. These compounds would be separated by bp.
The compounds must be soluble in a solvent and/or be able to be volatized in order to be separated by GC or LC. Esters are more volatile and are more easily dissolved than carboxylic acids.